Prophecy Kryptos: Solving Kryptos K4, Tongues Confirmation, and Practical Persuasion
Part 3.
Practical Persuasion

      Welcome to "Prophecy Kryptos: Solving Kryptos K4, Tongues Confirmation, and Practical Persuasion."  Suggestion: begin with Part 1. Solving Kryptos K4.  The analysis of Kryptos K4 (the part 4 coding) is a demonstration of what we can achieve when we simply play mathematically and verbally with letters.  On this page's Part 3. Practical Persuasion, to understand and explain the comfort of the solution of K4, we will examine some Kryptos clues as confirmations of the most clear prophetic words of knowledge which we have determined.

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Part 3. Practical Persuasion

3.a. The K1, K2, and K3 Solutions (K1, K2, and K3, respectively) and K4 Contain Clues About the Creation of BROOKLYNOK

      Examining the solutions to K1, K2, and K3 (K1, K2, and K3, respectively) and K4 for clues to solve K4 is tedious, and one may never know whether one has found all such clues.  Following are K1 through K3 and K4 itself with some of the clues which I found in these sources.  Review all of Part 1.

K1  BETWEEN SUBTLE SHADING AND THE ABSENCE OF LIGHT LIES THE NUANCE OF IQLUSION

K2  IT WAS TOTALLY INVISIBLE HOWS THAT POSSIBLE ? THEY USED THE EARTHS MAGNETIC FIELD X THE INFORMATION WAS GATHERED AND TRANSMITTED UNDERGRUUND TO AN UNKNOWN LOCATION X DOES LANGLEY KNOW ABOUT THIS ? THEY SHOULD ITS BURIED OUT THERE SOMEWHERE X WHO KNOWS THE EXACT LOCATION ? ONLY WW THIS WAS HIS LAST MESSAGE X THIRTY EIGHT DEGREES FIFTY SEVEN MINUTES SIX POINT FIVE SECONDS NORTH SEVENTY SEVEN DEGREES EIGHT MINUTES FORTY FOUR SECONDS WEST X LAYER TWO

K3  SLOWLY DESPARATLY SLOWLY THE REMAINS OF PASSAGE DEBRIS THAT ENCUMERED THE LOWER PART OF THE DOORWAY WAS REMOVED WITH TREMBLING HANDS I MADE A TINY BREACH IN THE UPPER LEFT HAND CORNER AND THEN WIDENING THE HOLE A LITTLE I INSERTED THE CANDLE AND PEERED IN THE HOT AIR ESCAPING FROM THE CHAMBER CAUSED THE FLAME TO FLICKER BUT PRESENTLY DETAILS OF THE ROOM WITHIN EMERGED FROM THE MIST X CAN YOU SEE ANYTHING Q ?

                                                      O B K R
U O X O G H U L B S O L I F B B W F L R V Q Q P R N G K S S O
T W T Q S J Q S S E K Z Z W A T J K L U D I A W I N F B N Y P
V T T M Z F P K W G D K Z X T J C D I G K U H U A U E K C A R

      In K2 the letter X appears alone 5 times, having its last appearance as X LAYER TWO, meaning that there are unknown letters X appearing 5 times = 5 X = 5 letters by the same pattern twice.  In K3 the letter X appears alone 1 time, having its only appearance as MIST X = MISSED X, meaning that of the determination of the unknown first 5 letters and the unknown second 5 letters, 1 of each set of 5 unknown letters will be missed, or found differently.  This description is of the 1 step, 4 steps, 4 steps, and 1 step, adding to the 10 steps used to find BROOKLYNOK.

      Having analyzed K4 for 2-letter words lines 2 and 4 until lines 1 and 4, I found OT, UP, OD, PU, and OK to spell TO, UP, DO, UP, and OK.  I rearranged the anagram of all 5 words into the following 4-word clue:

      TOUPDOUPOK = DOUPUPTOOK = DO 2UP TO OK = DO UP TO 2 OK = DO UP TO 2 _ OK = DO UP TO _ _ OK = DO UP TO OK

      In K3 DESPARATLY is misspelled word 2, and we count 2 to arrive at the first letter B in BOOK.  In K1 IQLUSION is misspelled word 13, and we count 13 from B to arrive at the second letter O in BOOK.  In K2 UNDERGRUUND is misspelled word 20, and we count 20 from the second letter O in BOOK to arrive at a letter O which is not one which I used but which would help to spell BOO toward spelling BOOK.  Now, counting letters from the end to the beginning, count 20 to a letter K which I did not use, count 13 to a letter Y which I did use, and count 2 to a letter B which I did not use. Notice that now we have BOOK and YB = why B, which is our starting letter, that's why; anyway, OKB lets us know that B begins while OK ends BROOKLYNOK, and BOY clues us in about JOE KID.  The fact that there are 3 misspelled words (also, 3 ? in K2) means that there are 3 legitimate sought after rewards: OUR FOX TRACKS IO GOOD AIDS TO WIN A CIGAR, TV, OUR PRO WON, and POINT IS CHECKS.  

      The misspelled words are in K1 ILLUSION as IQLUSION, in K2 UNDERGROUND as UNDERGRUUND, and in K3 DESPERATELY as DESPARATLY with _ for the missing letter E.  The anagram LQOUEA_ = EQUAL_O = EQUAL IO, meaning that the solution to K4 of BROOKLYNOK has 10 letters.  The missing letter E is a clue to determine why OUR FOX TRACKS IO GOOD AIDS TO WIN A CIGAR is missing the 5th letter of the English alphabet. 

      Selecting 2-letter words from lines 1 and 2, lines 2 and 3, and lines 3 and 4 in K4, we find OK, RO, OK, TV, and AT to spell OK, OR, OK, TV, and AT.  I rearranged the anagram of all 5 words into the following 5-word clue to TV, OUR PRO WON:

      OKOROKTVAT = AT OR TV OKOK =  AT OR TV OKOK I = A+ OR TV OKOK I = A+ OR TV OK'S I = A+ OR TV OK'S FIRST

      There is another clue to the twice repeated pattern in the 10 steps: in K4, column 15 spells BAT, column 19 spells ILL, column 20 spells RUG, and column 25 spells AIR so that 19 - 15 = 4, 20 - 19 = 1, and 25 - 20 = 5.  The 4 columns mean that there are 4 moves of 1 step, 4 steps, 4 steps, and 1 step, adding to the 10 steps used to find BROOKLYNOK.  Yet, I rearranged the anagram of all 4 words into the following 4-word clue to POINT IS CHECKS:  

      BATILLRUGAIR = TBUGLIARLIAR = T BUG LIARS = + BUG LIARS = PP BUG LIARS = CHECKS BUG LIARS 

There is already another word of knowledge by interpretation of tongues of the anagram BATILLRUGAIR irrelevant to this prophecy.

3.b. The Solution of K2 (K2) Contains a Clue About the Relevance of NY

      In K2 the part of the coordinates with the decimal point is 6.5" N, meaning the following:

      6.5" N = 6 point 5 seconds N = points N second 65 = points NY = point's NY = POINT IS NY

Notice that in K4 after the 1st letter N in NY comes the 2nd letter Y in NY, which is the 65th letter in K4.  When recircling K4, I did come 1st to N and 2nd to Y to get BROOKLYNOK.  Review Conquering Kryptos K4 in Part 1

      Notice also that we can account for both the 5 and the 6.  The full K2 coordinates are in the courtyard of the CIA.  Not only does C, the 3rd letter of the English alphabet, plus I, the 9th letter of the English alphabet, plus A, the 1st letter of the English alphabet, add to 13, but 13 x 5 = 65.  As for the 6, N, the 14th letter of the English alphabet, plus Y, the 25th letter of the English alphabet, add to 39, but 39 = 3 x 13, not the double 6 x 13, because despite Brooklyn being 1 of 5 boroughs which comprise the city called NY in the state also called NY, only 1 NY of these 2 NY's (I/2 of NY's) is mentioned in POINT IS NY.

3.c. The Solution of K3 (K3) Contains Clues to Actually Create BROOKLYNOK 

      K3 can be tediously scrutinized to reveal the letters needed in the solution of K4.

      DESPARATLY = DESPARAT_LY = ESP data R - ly = R   

      BREACH = reach B = B      

      WIDENING THE HOLE A LITTLE I INSERTED = widening the o a little _ inserted = O

      PEERED IN = peered one N = N

      THE HOT AIR ESCAPING FROM THE CHAMBER = oxygen = O2 = 2 O = OO

      PRESENTLY = present LY = LY

      MIST X = missed X = missed letter = ?

      (CAN YOU SEE ANYTHING Q? = IO?  No, so far we have only 8 letters.) 

      I rearranged the anagram of all 8 letters plus missed letter ? into the following clue:

      RBONOOLY? = BROO?LYNO = BROOKLYNOK

Notice that ? = K, which we supply.  Notice also that ? = K, which we replace, because from THE REMAINS OF PASSAGE (K3) DEBRIS (K) THAT ENCUMBERED THE LOWER PART OF THE DOORWAY (_) WAS REMOVED = K WAS REMOVED.  Review Conquering Kryptos K4 in Part 1.     

3.d. There is a Finding of James Sanborn, the Sculptor of "Kryptos" Dedicated 1990   

      In K4 Q appears 4 times as QQ, Q, and Q, and since QQ = cues, we have to follow up on Q and Q, which are 3 places apart, while the first and last Q are 17 places apart.  In K3 CAN YOU SEE ANYTHING Q? had me questioning in 3.c. whether Q? = IO?  Since Q is the 17th letter of the English alphabet, I also have to question whether Q? = 17?  We can associate IO and 17 with K4, after we count the letters of the English alphabet as follows:

      KRYPTOS = 11 + 18 + 25 + 16 + 20 + 15 + 19 = 124

      J A M E S   S A N B O R N = 10 + 1 + 13 + 5 + 19   +   19 + 1 + 14 + 2 + 15 + 18 + 14 = 48   +   83 = 131

      124 - 10 = 114      114 + 17 = 131

Notice how KRYPTOS is found in K4, reading K, R, Y, and P in green as soon as they occur from beginning to end, and reading T, O, and S in blue--with the first T showcased as the 17th letter--from end to beginning:

                                                      O B K R
U O X O G H U L B S O L I F B B W F L R V Q Q P R N G K S S O
T W T Q S J Q S S E K Z Z W A T J K L U D I A W I N F B N Y P
V T T M Z F P K W G D K Z X T J C D I G K U H U A U E K C A R

      We can arrive at the instrumental numbers of the 10-step pattern used: 1, 4 and 5.  T stands alone as 1 letter.  S is the 19th letter of the English alphabet, O is the 15th letter of the English alphabet, and 19 - 15 = 4.  Also, 19 + 15 = 34.  K is the 11th letter of the English alphabet, R is the 18th letter of the English alphabet, and 11 + 18 = 29.  34 - 29 = 5.  Here omitted from KRYPTOS are Y and P.

      By a stretch of imagination, we can also arrive at the year the sculpture was dedicated as follows:

      124 + 131 = 255      255 x 8 = 2040      10 x 5 = 50      2040 - 50 = 1990

Notice that 8 + 5 = 13, the factor instrumental at the beginning of my quest for BROOKLYNOK, while I had found in my search for a first reward 8 words from the beginning to the end of K4 and 5 words from the end to the beginning of K4.  As for 17, 17 - 13 = 4, another number instrumental at the beginning of my quest for BROOKLYNOK.  Furthermore, Y and P form the 3rd set of letters comprising the word "kryptos."  Y is the 25th letter of the English alphabet, P is the 16th letter of the English alphabet, and 25 + 16 = 41.  The 3 and the 41 can be rearranged to form 13 and 4, or PY = (Greek letter) pi = 3.14 = 3 point 14 = Point: 13  4. 

 3.e. Comment

      When I got extraordinarily creative, I resorted to a zigzag mode from each of the 4 corners and found BED, IWT, KO, WEO, MTO, OT, and OEW to spell BED, WIT, OK, OWE, TOM, TO, and OWE.  I quickly rearranged the anagram of all 7 words into the following 6-word comment:

      BEDWITOKOWETOMTOOWE = OK.  TIME TO BE WOWWED, TOO.

Review 3.c.  Notice that the 7 words correspond to the 7 clues in K3, while the 6 words correspond to the 6 immediately known clues there except for ?.  Notice also that while I from K and I from K add to the 2 letters in OK., it is also true that 7 from 7 clues, 6 from 6 immediately known clues, and 4 from 4 corners add to the 17 letters in TIME TO BE WOWWED, TOO.  I finally noticed on 07-25-12 that these 5 words are comprised of 4 words and 1 word separated by a comma, after the 2 letters in OK. 

      When I spotted that all along the 1st letter O = IO, I stopped looking for clues and connections on 07-26-12, 1 day before going on the Internet on 07-27-12. 

      Part 1. Solving Kryptos K4

      Part 2. Tongues Confirmation (Tongues Confirms Kryptos Interpretations) 

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page content: online 07-27-12, last revised 01-07-13